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Welcome to my articlex(x+1)(x+2)(x+3)÷x(x+1)
This article has been taken from the simplification lesson, in this article we have been told to simplify with the action of addition, subtraction, multiplication, division and fractions.
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Let us read / understand about this article x(x+1)(x+2)(x+3)÷x(x+1)
x(x+1)(x+2)(x+3)÷x(x+1)
Let’s solve it by putting it like this,
\displaystyle x(x+1)(x+2)(x+3)=x(x+1)Taking x (x + 1) common to both the sides,
\displaystyle x(x+1){(x+2)(x+3)}=x(x+1){1}Normally taken posts are removed from both sides,
\displaystyle {(x+2)(x+3)}={1} \displaystyle (x+2)(x+3)=1Now in this question,
If ,(x +2 )=1
So ,
x =1-2
x=-1 answer
And
If ,
(x +3 )=1
So ,
x =-2 answer
This article x(x+1)(x+2)(x+3)÷x(x+1) has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.
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HOW TO SLOVE x(x+5)(x+6)(x+2)÷x(x+5)(x+2) ?
First of all we should write the article on the page of the notebook.
x(x+5)(x+6)(x+2)÷x(x+5)(x+2)
Let’s solve it by putting it like this,
\displaystyle x(x+5)(x+6)(x+2)=x(x+5)(x+2)Taking x (x + 5)(x+2) common to both the sides,
\displaystyle {x\left( {x+5} \right)\left( {x+2} \right)}\left( {x+6} \right)=x\left( {x+5} \right)\left( {x+2} \right){1}Normally taken posts are removed from both sides,
\displaystyle x+6=1Now in this question,
If ,(x +6 )=1
So ,
x =-5 answer
How to solve x(x+1)(x+2)(x+3)÷x(x+1) This article x(x+5)(x+6)(x+2)÷x(x+5)(x+2) has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.
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See other similar examples (2)
x(x+1/3)(x+2/5)(x+5/2)÷x(x+1/3)(x+5/2)
First of all we should write the article on the page of the notebook.
x(x+1/3)(x+2/5)(x+5/2)÷x(x+1/3)(x+5/2)
Let’s solve it by putting it like this,
\displaystyle x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{2}{5}} \right)\left( {x+\frac{5}{2}} \right)=x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{5}{2}} \right)Taking x (x + 1/3)(x+5/2) common to both the sides,
\displaystyle {x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{5}{2}} \right)}\left( {x+\frac{2}{5}} \right)={x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{5}{2}} \right)}(1)Normally taken posts are removed from both sides,
\displaystyle \left( {x+\frac{2}{5}} \right)=(1) \displaystyle x+\frac{2}{5}=1Now in this question,
If ,(x +2/5 )=1
So ,
\displaystyle x=1-\frac{2}{5}
How to solve x(x+1)(x+2)(x+3)÷x(x+1) This article x(x+1/3)(x+2/5)(x+5/2)÷x(x+1/3)(x+5/2)has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.
Note: If you have any such question, then definitely send it by writing in our comment box to get the answer.
Your question will be answered from our side.
Thank you once again from our side for reading or understanding this article completely.
